The length of a rectangle is shown below:

on a coordinate grid from negative 6 to positive 6 on the x-axis and on the y-axis, two points a and b are shown. the point a is on ordered pair negative 1, 2 and the point b is on ordered pair 2, 2.

if the area of the rectangle to be drawn is 12 square units, where should points c and d be located, if they lie vertically below a and b, to make this rectangle?

a. c(2, −2), d(−1, −2)
b. c(2, −1), d(−1, −1)
c. c(−2, 2), d(−2, −1)
d. c(−1, 2), d(−1, −1)

The answer is option A. C(2, −2), D(−1, −2)

Step-by-step explanation:

The length of AB = 3 units

The area of the rectangle to be drawn is 12 square units

So, the width = The area/The length = 12/3 = 4 units

C and D be located vertically 4 units below A and B

So, C and D like the image of A and B with a transformation rule

(x,y) → (x , y-4)

The coordinates of A(-1,2) and B(2,2)

So, C and D are: (-1,-2) and (2,-2)

The answer is option A. C(2, −2), D(−1, −2)

idk the answer but just put a

step-by-step explanation:

yes. we do proportions in probabilities.