Given that z is a standard normal random variable, find z for each situation (to 2 decimals). the area to the left of z is .2119.

Given that z is a standard normal random variable,

the area to the left of z is .2119.

The area to the left of z is given and we need to find out the z-score

To find z we use z-score table

z- score table is attached below.

We look at the z- score that has value 0.2119

From the table we can see that 0.2119 has z-score -0.80

the area to the left of -0.80 is .2119.

(x, y)→(x − 8, y − 7)

step-by-step explanation:

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