Suppose that during a test drive of two cars, one car travels 186 miles in the same time that the second car travels 150 miles. if the speed of one car is 12 miles per hour faster than the speed of the second car, find the speed of both cars.

Algebra: Exponent and logarithm as functions of archive   
 
Click here to see ALL problems on Exponential-and-logarithmic-functionsQuestion 726619: Skid mark analysis is one way to estimate the speed a car was traveling prior to an accident. The speed, s, that the vehicle was traveling in miles per hour can be approximated by the formula s=square root 30df, where d represents the length of the skid marks in fee and "f" represents the drag factor of the road. A vehicle that was involved in an accident on an asphalt road was traveling at a speed of 45 mph when it started skidding. If the drag factor for asphalt is 0.75 find the length of the skid marks made by the car. The skid marks made by the car were approximately feet long. 
Answer by stanbon(75310)   (Show Source):You can put this solution on YOUR website!
s=square root 30df, where d represents the length of the skid marks in feet and "f" represents the drag factor of the road. A vehicle that was involved in an accident on an asphalt road was traveling at a speed of 45 mph when it started skidding. If the drag factor for asphalt is 0.75 find the length of the skid marks made by the car.
S = sqrt(30df) 
45 = sqrt(30*d*0.75)

45 = sqrt[(90/4)d]

45 = (3/2)sqrt(10d)
30 = sqrt(10d)
10d = 900
d = 90 ft.