*an isosceles trapezoid abcd has bases ad = 17 cm, bc = 5cm, and leg ab = 10cm. a line is drawn through vertex b so that it bisects diagonal ac and intersects ad at point m. find the area of δbdm.

The area of the trapezoid is 88 cm^2.

To do this problem, first draw out the picture. Then, you will see that the legs of the triangle form a 6, 8, 10 Pythagorean Triple triangle. That gives us the height of the trapezoid as 8.

To find the area of the trapezoid, we can use the equation:

A = 0.5(8)(5 + 17)
A = 88 cm^2