Mathematics, 24.07.2019 15:30, aprilpendergrass
The zeros of a parabola are 6 and β5. if (-1, 3) is a point on the graph, which equation can be solved to find the value of a in the equation of the parabola? 3 = a(β1 + 6)(β1 β 5) 3 = a(β1 β 6)(β1 + 5) β1 = a(3 + 6)(3 β 5) β1 = a(3 β 6)(3 + 5)
Answers: 1
Mathematics, 21.06.2019 16:20, angelb2472
Consider the function y = f(x)=3^x the values of f(1/2) and f(1/4). rounded to the nearest hundredth, are__and__ respectively
Answers: 3
Mathematics, 21.06.2019 20:30, maxy7347go
Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [β1, 1] no, f is continuous on [β1, 1] but not differentiable on (β1, 1). no, f is not continuous on [β1, 1]. yes, f is continuous on [β1, 1] and differentiable on (β1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.
Answers: 1
Mathematics, 21.06.2019 22:30, tanionxavier
The track team ran a mile and a quarter during their practice how many kilometers did her team runs?
Answers: 1
The zeros of a parabola are 6 and β5. if (-1, 3) is a point on the graph, which equation can be solv...
Mathematics, 15.04.2020 17:26
English, 15.04.2020 17:26
Mathematics, 15.04.2020 17:26
Chemistry, 15.04.2020 17:26