Hey guys, i have been having some trouble with this question related to quadratic formulas. its a 3 part question, but i only want the first part done, so i can do the rest. here is the question:

3. a rocket is launched vertically from the ground with an initial velocity of 64 .
(a) write a quadratic function h(t) that shows the height, in feet, of the rocket t seconds after it was launched.

you so much in advance. i really appreciate it.

To find the height that the rocket has reached, we can use the following equation to calculate distance.
s = ut + 1/2 at²
s - distance - h
u - initial velocity  - 64 ft/s x 0.3048 m/ft = 19.5 m/s
a - acceleration, since the rocket is travelling upwards against gravitational acceleration, its said to be deceleration. therefore value is -9.8 ms⁻²
t - time taken  - t seconds
substituting values in the equation
h = 19.5 ms⁻¹ x t s - 1/2 x 9.8 ms⁻² x (t s)²
h = 19.5t - 4.9t²

There is not enough information on this sorry can you take a picture of it and put it on here

Ineed show the photo because i need more information