Acompound experiment consists of tossing a coin, drawing a letter at random from the alphabet, and then tossing two coins. what is the probability of getting a tail, the letter t, and then two tails? 1/156 1/208 1/52

Given that there are three different games played.

Game 1: Toss a coin

Game 2: Drawing a letter at random from the alphabet

Game 3: Toss two coins

From first game we need to get "tail"

we know that there are two possible cases when tossing any coin {Head , Tail}

So probability of getting tail = 1/2

From second game we need to get letter "T"

we know that there are total 26 alphabets

So probability of getting letter T = 1/26

From third game we need to get two "tail"

Possible cases are {HH, HT, TH, TT} which are 4

H means Head T means tail. We see that double tail occurs only once from 4 possible cases

So probability of getting two tail = 1/4

Now we can combine all the results to find the probability of getting a tail, the letter T, and then two tails

Hence final answer will be

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

what do u need to know

step-by-step explanation: