The midpoint of 2004-06-02-01-00_files/i0190000.jpg is (14, 26). one endpoint of 2004-06-02-01-00_files/i0190001.jpg is a(32, 40). what are the coordinates of b?

Midpoint: M=(14,26)=(xm,ym)→xm=14, ym=26
One endpoint: A=(32,40)=(xa,ya)→xa=32, ya=40)
Other endpoint: B=(xb,yb)→xb=?; yb=?

xm=(xa+xb)/2
Replacing xm=14, and xa=32
14=(32+xb)/2
Solving for xb. Multiplying both sides of the equation by 2:
2(14)=2(32+xb)/2
28=32+xb
28-32=32+xb-32
-4=xb
xb=-4

ym=(ya+yb)/2
Replacing ym=26, and ya=40
26=(40+yb)/2
Solving for yb. Multiplying boths sides of the equation by 2:
2(26)=2(40+yb)/2
52=40+yb
52-40=40+yb-40
12=yb
yb=12

B=(xb,yb)→B=(-4, 12)

the coordinates of B are (4,12)

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.