What amount of charge moves through an electric fan in 15.1 s if the current through the fan is 1.27 a? a. 084c c. 19.2c b. 11.9c d. 1.82c

Given that current through fan I = 1.27 A

Time of the current flow = 15.1 s

Now we have to find the value of charge that moves through an electric fan in 15.1 s if the current through the fan is 1.27 A.

We know that current (I) is the rate of flowing of charge (Q) with time (t) through a section of a conductor.

which is given by formula

Plug the given values

Hence answer is approx 19.2 C.

i would say the third one.

step-by-step explanation: liner would mean in a line and the only one that doesn't look like it's even thinking about forming a line would be the third one

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?