Evaluate ∫ cot 2x dx. a. 1⁄2 ln csc 2x + c b. 1⁄2 ln cos 2x + c c. 1⁄2 ln sin 2x + c d. 1⁄2 ln sec 2x + c

Cot(2x)dx = [cos(2x) / sin(2x)] dx, and note that the derivative of sin(2x) = 2cos(2x)dx, which is double of the numerator.
Therefore, this can be integrated using an ln function of sin. This results in:
(1/2)ln(sin2x) + C
This is choice C.

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