Find the range of the quadratic function. f(x) = (x + 8)2 - 7

[-7, ∞ )

Step-by-step explanation:

I'm assuming that the function is y = (x + 8)² - 7

To find the range, we need to find the vertex,

Vertex form of a quadratic equation is y = a(x - h)² + k, where (h, k) is the location of the vertex.  Our equation has a = 1, h = -8, and k = -7.  Since a > 0, the parabola opens up, so the upper limit of the range is infinity.  To find the lowest value of the range, we find the vertex.  

Here the vertex is at point (-8, -7), so -7 is the lower limit of the function's range.

The range is [-7, ∞ )

2? if not the correct answer you might need to provide more information

step-by-step explanation:

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: