For a standard normal distribution, find the approximate value of p(-0.78 = z = 1.16). use the portion of the standard normal table below to answer the question. (z) 0.00 0.16 0.22 0.78 1.00 1.16 1.78 2.00 (probabilities) 0.5000 0.5636 0.5871 0.7823 0.8413 0.8770 0.9625 0.9772

Correction:

I think the question should be like that find the approximate value of

P(-0.78 < z < 1.16)?

Now,

the symbol Ф represent the cumulative density.

first find the

Ф(1.16) from the above given table which is equal to 0.8770.

Now,

find the Ф(-0.78) .

in our table we are given the value of Ф(0.78)=0.7823

so as the curve is symmetrical Ф(-0.78)=1-0.7823=0.2177

P(-0.78 < z < 1.16) = Ф(1.16)-Ф(-0.78)

= 0.8770-0.2177

= 0.6593

i just took the test, the correct answer is .. 31.5 in.