The floor of a trianaglular room has an area of 32 1\2 sq. m. if the triangle altitude is 7 1\2 m weite an equation to determine the length of the base, b, in metere. then solve the equation

You must follow the proccedure shown below to solve this problem:

 You have that the floor of a triangular room has an area of 32 1\2 m² If the triangle altitude is 7 1\2 m. Then, you have:

 A=32 1/2 m²=32.5 m²
 h=7 1/2 m=7.5 m

 Now, you can calculathe b as below:

 A=bxh/2
 b=Ax2/h

 When you substitute the values, you obtain:

 b=32.5 m²x2/7.5 m
 b=65 m²/7.5 m
 b=8.66 m

The sum is 2,160, no problem

Ibelieve that the answer is 1 but i could be wrong