Mathematics, 25.07.2019 12:30, 1341220857

Asap! a line is drawn so that it passes through the points (-3,-1) and (4,2). a. what is the slope of the line? b. using the point (4,2) and the slope found above, write the equation of the line in point-slope form. write out how you got your answer or the steps you took.

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A) To find slope, use the equation: $slope = \frac{ y_{2} - y_{1} }{x_{2}-x_{1}}$ where $x_{2}$ and $y_{2}$ are the x and y values of one coordinate point , and $x_{1}$ and $y_{1}$ are the x and y values of another coordinate point . Since we are given two coordinate points, (-3,-1) and (4,2), that means we can find the slope using the slope equation.
Let's choose (4, 2) as your $(x_{2}, y_{2})$ point and (-3, -1) as your $(x_{1}, y_{1})$ point, but you can switch those if you want! That makes $x_{2} = 4, y_{2} = 2$ and $x_{1} = -3, y_{1} = -1$ . Plug these values into the slope equation:
$slope = \frac{ y_{2} - y_{1} }{x_{2}-x_{1}} \\ slope = \frac{2-(-1)}{4-(-3)} \\ slope = \frac{3}{7}$

The slope of the line is 3/7.

B) Remember that the general equation for point-slope form is y - y_1 = m(x - x_1)

, where m = the slope, $x_{1}$ = the x value of a coordinate point $(x_{1}, y_{2})$ on the line, and $y_{1}$ = the y value of the same coordinate point on the line.

You are given (4, 2) as one of the coordinate points. That means $x_{1}$ = 4 and $y_{1}$ = 2. We found the slope, m = $\frac{3}{7}$ in part A. Now plug these values into the general equation for point-slope form to find your point-slope form equation:
$y - y_1 = m(x - x_1)\\
y - 2 = \frac{3}{7}(x - 4)$

Your point-slope form equation is $y - 2 = \frac{3}{7}(x - 4)$ .

answered: Guest

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you

answered: Guest

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: