Acircle has a diameter of 12 units, and its center lies on the x-axis. what could be the equation of the circle? check all that apply. (x – 12)2 + y2 = 12 (x – 6)² + y² = 36 x² + y² = 12 x² + y² = 144 (x + 6)² + y² = 36 (x + 12)² + y² = 144

Options 2 and 5.

Step-by-step explanation:

The standard form of a circle is

     ... (1)

where, (h,k) is center and r is radius.

We need to find the circle that has a diameter of 12 units, and its center lies on the x-axis.

So, radius of required circle must be 6 and center is in the form of (a,0).

The first equation is

      .... (2)

On comparing (1) and (2) we get  

Center of the circle is (12,0) and radius is . So, option 1 is incorrect.

Similarly,

For equation 2, center of the circle is (6,0) and radius is . So, option 2 is correct.

For equation 3, center of the circle is (0,0) and radius is . So, option 3 is incorrect.

For equation 4, center of the circle is (0,0) and radius is . So, option 4 is incorrect.

For equation 5, center of the circle is (-6,0) and radius is . So, option 5 is correct.

For equation 6, center of the circle is (-12,0) and radius is . So, option 6 is incorrect.

Therefore, the correct options are 2 and 5.

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

x=30

step-by-step explanation: