Can someone me solve this problem

The 1st choice would be TRUE - if we draw vertical lines down the graph, we can see that there are no points which touch the line more than once.

The 2nd choice would be FALSE - by looking at the graph, we can see that there is indeed x values which are less than 2

The 3rd choice would be TRUE - looking at the y values on the graph, there is no y value below 2

The 4th choice would be FALSE - intervals are points where the graph stops and begins to form another graph from that point (there may be a better definition of this than mine), and from the plot given, there is only one interval

The 5th choice would be FALSE - the straight line would definitely be a linear function, but the parabola is not, as it involves a curve

So your answers should be options 1 and 3

Hope this helped!

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4