The smaller of two similar rectangles has dimensions 4 and 6. find the dimensions of the larger rectangle if the ratio of the perimeters is 2 to 3. 2 2/3 by 4 6 by 9 8 by 18 12 by 12

6 by 9

I was stuck on thus question too for a while but then I went back and figured everything.

The correct option is B. 6 by 9

Step-by-step explanation:

Length of the smaller rectangle = 4 units

Width of the smaller rectangle = 6 units

Perimeter of the smaller rectangle = 2 ( length + width )

                                                          = 2 (4 + 6)

                                                          = 20 units

Now, the ratio of the smaller rectangle to the larger rectangle is 2 : 3

Let the perimeter of larger rectangle be x units

⇒ 20 : x = 2 : 3

⇒ x = 10 × 3

⇒ x = 30 units

Now, Perimeter of larger rectangle = 30 units

⇒ 2 ( L + B) = 30

⇒ L + B = 15 units

Hence, from the given options only option B. gives the L + B = 15 units.

Therefore, The dimensions of larger rectangle = 6 by 9

Hence, The correct option is B. 6 by 9

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

111

step-by-step explanation: