Which triangles are congruent by asa?

ΔABE ≅ ΔDEA

Step-by-step explanation:

From the given picture, In Δ ACE we have AC= CE

Then, ∠A=∠E     (1)  [∵Angles opposite to equal angles of a triangle are equal.]      

Also, it is given that ∠B=∠D=90°    [Right angle]

Now, Consider ΔABE and ΔDEA

Here,

∠A=∠E      [From (1)]

AE=AE         [By Reflexive property]

∠B=∠D=90°   [given]

Then, by ASA congruence postulate , ΔABE ≅ ΔDEA

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w