1. graph the function f(x) =x^2 +4x-12 on the coordinate plane (a) what are the x-intercepts? (b) what is the y-intercept? (c) what is the maximum or minimum value? for a i think they would be -6,0 and 2,0 for b i think it would be -2,-16 and 0,-12 i dont know for c am i

part a) the x-intercepts are the points and

part b) the y-intercept is the point

part c) the minimum value is the point

step-by-step explanation:

we have

using a graphing tool

see the attached figure

part a) what are the x-intercepts?

we know that

the x-intercepts are the values of x when the values of y is equal to zero

observing the graph

the x-intercepts are the points and

part b) what is the y-intercept?

the y-intercept is the value of y when the value of x is equal to zero

observing the graph

the y-intercept is the point

part c) what is the maximum or minimum value?

the graph show a vertical parabola open upward

so

the vertex is a minimum

the vertex is the point

therefore

the minimum value is the point

answer: 370

step-by-step explanation:

remember use pemdas! there are no parentheses or exponents so lets move onto the first part of the equation: multiplication and division. first, lets break the first part of the equation up into something easier using the distributive property. 28 * 12= (20 *12) + (8*12) you know that 20*12 is 240 and 8*12 is 96. add them and you get 336. then, lets solve the last part of the equation (the last part of pemdas is addition and subtraction). 336 plus 34 is 370. hope this !

x = -2

y = 848

step-by-step explanation:

plug in the numbers