Mathematics
Mathematics, 26.07.2019 01:00, isabelj2004

Which values of x are point(s) of discontinuity for this function? explain how you did it. g(x)= {-4, x< =-2} {-x^2, -2< x< 0} {x^2, 0< x< 2} {2, x> =2} answer choices (check all that apply): x=-4 x=-2 x=0 x=2 x=4hurry! will mark brainliest!  

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Which values of x are point(s) of discontinuity for this function? explain how you did it. g(x)=...

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