Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes, and one vertex in the plane x+6y+11z=66x+6y+11z=66. largest volume is

This is solved in the same fashion as link.
x = 22
y = 11/3
z = 2

The largest volume is 22*11/3*2 = 161 1/3 . . . . cubic units.


When the constraint is a plane, the x, y, z values for the maximum volume are 1/3 the x-, y-, z- intercepts.

What’s the question?

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to