Mathematics, 26.07.2019 04:30, davienwatson8
How many real number solutions does the equation have in 0 equals -7x ^ 2 + 6x + 3
Answers: 1
![7 x^{2} + 6x + 3 = 0 First step use cuadratic fomula x = [-b +- \sqrt{ b^{2} -4ac } ]/ 2a](/tpl/images/0133/6708/9a2ac.png)
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How many real number solutions does the equation have in 0 equals -7x ^ 2 + 6x + 3...
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