Mathematics
Mathematics, 26.07.2019 08:30, mahin3545

The work of a student trying to solve the equation 4(2x βˆ’ 1) = 11 + 3x + 5 is shown below: step 1: 4(2x βˆ’ 1) = 11 + 3x + 5 step 2: 8x βˆ’ 4 = 16 + 3x step 3: 8x + 3x = 16 βˆ’ 4 step 4: 11x = 24 step 5: x = 2.18 in which step did the student first make an error and what is the correct step?

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The work of a student trying to solve the equation 4(2x βˆ’ 1) = 11 + 3x + 5 is shown below: step 1:...

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