Answers: 2
![3x^2+12x-36=3(x^2+4x-12)=3(x^2+6x-2x-12)\\\\=3[x(x+6)-2(x+6)]=3(x+6)(x-2)](/tpl/images/0749/2029/0a4f0.png)
![3x^2 +12x-36=3(x^2+4x-12)=3(x^2-2x+6x-12)=\\\\=3[x(x-2)+6(x-2)]=3(x-2)(x+6)](/tpl/images/0749/2029/58029.png)
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