Mr. jameson is walking toward his nine-story hotel and stops to look up to the top of the building. the angle of elevation to the top of the hotel is 40°. if the height of the hotel is 90 feet, about how far away is mr. jameson from the hotel?

The problem can be modeled as a rectangle triangle where we know a side and an angle.
 We can use the following trigonometric relationship:
 tan (x) = (C.O) / (C.A)
 Where,
 x: angle
 C.O: opposite leg
 C.A: adjoining catheto
 Substituting values we have:
 tan (40) = (90) / (C.A)
 Clearing C.A:
 C.A = (90) / (tan (40))
 C.A = 107.2578233 feet
 
 Mr. Jameson is 107.2578233 feet from the hotel