How many factors in the expression 8(x+4)(y+4)(z2+4z+7)have exactly two terms

It helps to first identify the factors. They are:

- 8
- (x + 4)
- (y + 4)
- (z² + 4z + 7)

Terms are separated by "+" and "-" signs, so that eliminates the first factor, which only has one term. The fourth factor has two "+" signs, and as you can see, it has three terms; that one is out as well. The last two factors both have only one "+" sign, and they both have two terms. Therefore...

Two factors in the expression 8(x + 4)(y + 4)(z² + 4z + 7) have exactly two terms.