Which of the following functions has a maximum at x=3? select all that aplly. a. f(x)= (x-3)^2 b. f(x)= (x-2)(4-x) c. f(x)= -x^2+6x-5 d. f(x)= 1-(x-3)^2 e. f(x)= (x+3)^2-9 f. f(x)= x^2-4x+3

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116