Which statement is always true about the graph of an equation in the form y=kx? a)the point (0,k) is on the graph. b)the point (1,1) is on the graph. c)the point (k,0) is on the graph d)the point (0,0) is on the graph.

d)The point (0,0) is on the graph.

Step-by-step explanation:

Select statement is always true about the graph of an equation in the form y=kx

(0,k)  , x=0  and y=k

LEts plug in x=0 in y= kx

y=k(0) =0, so the point (0,k) on the graph of y=kx is not true

(1,1)  , x=1  and y=1

LEts plug in x=1 in y= kx

y=k(1) =k, so the point (1,1) on the graph of y=kx is not true

(k,0)  , x=k  and y=0

LEts plug in x=k  in y= kx

y=k(k) =k^2, so the point (k,0) on the graph of y=kx is not true

(0,0)  , x=0  and y=0

Lets plug in x=0 in y= kx

y=k(0) =0, so the point (0,0) on the graph of y=kx is true

168

step-by-step explanation:

first off, we know that he drove 3.5 hours at a rate of 48 mph.

knowing that, we want to see how many miles he drove all-together.

in this case, we can just multiply 48 by 3.5.

48 * 3.5 = 168