Find the 6th term of the geometric sequence whose common ratio is 1/3 and whose first term is 2.

To solve for geometric sequences, use the formula an = a1r^(n - 1), where a1 = first term, n = position number of given term, r = common ratio, and an = value of term in given position.

For this problem, a1 = 2, n = 6, and r = 1/3. Now, plug those values into the equation and solve.

a6 = 2(1/3)^(6 - 1)
a6 = 2(1/3)^(5)
a6 = 2(0.00411522633)
a6 = 0.00823045267

I hope this answers your question.