1. a dilation with a scale factor of 4 and centered at the origin is applied to ab with endpoints a(1, 3) and b(5, 3). drag and drop to match each point with its correct coordinates.

2. rectangle abcd has vertices a(1, 2) , b(4, 2) , c(1, −2) , and d(4, −2) . a dilation with a scale factor of 6 and centered at the origin is applied to the rectangle.

which vertex in the dilated image has coordinates of (24, 12) ?

a′

b′

c′

d′

3. line segment ab has endpoints a(1, 4) and b(2, 8) . a dilation, centered at the origin, is applied to ab . the image has endpoints a′(18, 12) and b′(14, 1) .

what is the scale factor of the dilation?

18

12

2

8

4. the larger triangle is a dilation of the smaller triangle with a center of dilation at (2,−1) .

what is the scale factor of the dilation?

13

12

2

3

the dilation one is the top and the triangle one is the #4

1. A'(4, 12)  and B'(20, 12)

2. B'

3. 1/8

4. 2

Step-by-step explanation:

1.  

A(1, 3) -> A'(1*4, 3*4) = A'(4, 12)

B(5, 3) -> B'(5*4, 3*4) = B'(20, 12)

where 4 is the scale factor , that is, x-coordinate of A' is x-coordinate of A multiplied by the scale factor, and so on.

2.

B(4, 2) -> B'(4*6, 2*6) = B'(24, 12)

3.  

A(1, 4) -> A′(1/8, 1/2)

B(2, 8) -> B′(1/4, 1)

factor = (1/8)/1 = (1/2)/4 = (1/4)/2 = 1/8

4.

distance between point (2,2) and the center of dilation (2, -1) is 3

distance between point (2,5) and the center of dilation (2, -1) is 6

factor = 6/3 = 2

your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.