Shenelle has 100100100 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of the garden's width www (in meters) is modeled by: a(w)=-(w-25)^2+625a(w)=−(w−25) 2 +625a, left parenthesis, w, right parenthesis, equals, minus, left parenthesis, w, minus, 25, right parenthesis, start superscript, 2, end superscript, plus, 625 what is the maximum area possible?

625 sq. m.

Step-by-step explanation:

The graden's area is given as :  

For maximization of area,we need to put first order derivative of given equation equals to 0 i.e. a'(w) should be equal to zero.  

On Simplifying :

w = 25 meters

Since we are given that Shenelle has 100 meters of fencing to build a rectangular garden

This means perimeter is equal to 100.

Formula of perimeter of rectangle :

Where l is length

w is width

Plugging w as 25

Dividing 2 in both sides

So, for the maximum area the length should be 25 m and width should 25 m

So, So, maximum area

Hence the maximum possible area is 625 sq. m.

hard

step-by-step explanation:

the answer is:

the lateral area is equal to

to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:

where,

s, is the base length

slant height, is the height of a the side of the pyramid

we are given:

now, calculating the perimeter of the base, we have:

then, calculating the lateral area:

hence, we have that the lateral area is equal to

have a nice day!