Which value or values for the variable c from the set below will make 5.6 + 0.4c ≤ to 6c true? {0, 0.875, 1, 2.5

We are given this inequality here,

Now we have to check for the given values of c, that is true for this inequality.

1. when c=0

LHS: 5.6 + 0.4c

= 5.6+0.4(0)

=5.6

RHS: 6c =6(0)=0

5.6≤0

Not true for c=0.

2. when c=0.875

LHS: 5.6 + 0.4c

= 5.6+0.4(0.875)

=5.95

RHS: 6(0.875) =5.25

5.95≤5.25

Not true for c=0.875

3. when c=1

LHS: 5.6 + 0.4c

= 5.6+0.4(1)

=6

RHS: 6c =6(1)=6

6≤6

True for c=1.

4. when c=2.5

LHS: 5.6 + 0.4c

= 5.6+0.4(2.5)

=6.6

RHS: 6c =6(2.5)=15

6.6≤15

True for c=2.5.

The given inequality is true for c=1 and c=2.5

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.