The base of a soup can has an area of 9π in 2 and a height of 10 in. find the area for the label needed to wrap around the can with no overlaps.

soup can is in the shape of cylinder

given, base area = 9 pi

base area = area of circle = pi * r^2 = 9 * pi

r = 3

total surface area of cylinder = 2 *pi*r(h+r)

= 2*3(10+3) pi=  78 pi

area for the label needed to wrap around the can with

no overlaps 78 pi inches^2

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: