Mathematics, 27.07.2019 04:30, liapis2002
Given: f(x) = 2x + 5 and g(x) = x 2 and h(x) = -2x h(g(f( =
Answers: 2
![\bf \begin{cases} f(x)=2x+5\\ g(x)=x^2\\ h(x)=-2x\\ ---------------\\ g(~~f(x)~~)=[f(x)]^2\\ \qquad \qquad \qquad [2x+5]^2\\ h(~~g(~~f(x)~~)~~)=-2~([2x+5]^2) \end{cases} \\\\\\ h(~~g(~~f(x)~~)~~)=-2(2x+5)(2x+5) \\\\\\ h(~~g(~~f(x)~~)~~)=-2(\stackrel{FOIL}{4x^2+20x+25}) \\\\\\ h(~~g(~~f(x)~~)~~)=-8x^2-40x-50](/tpl/images/0137/5264/5c92d.png)
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Given: f(x) = 2x + 5 and g(x) = x 2 and h(x) = -2x h(g(f( =...
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