Y=4050x+2949 y=5165x+93 solve using the elimination method and the substitution method.

Solve the following system using elimination:
{y = 4050 x + 2949 | (equation 1)
{y = 5165 x + 93 | (equation 2)

Express the system in standard form:
{-(4050 x) + y = 2949 | (equation 1)
{-(5165 x) + y = 93 | (equation 2)

Swap equation 1 with equation 2:
{-(5165 x) + y = 93 | (equation 1)
{-(4050 x) + y = 2949 | (equation 2)

Subtract 810/1033 × (equation 1) from equation 2:
{-(5165 x) + y = 93 | (equation 1)
{0 x+(223 y)/1033 = 2970987/1033 | (equation 2)

Multiply equation 2 by 1033:
{-(5165 x) + y = 93 | (equation 1)
{0 x+223 y = 2970987 | (equation 2)

Divide equation 2 by 223:
{-(5165 x) + y = 93 | (equation 1)
{0 x+y = 2970987/223 | (equation 2)

Subtract equation 2 from equation 1:
{-(5165 x)+0 y = (-2950248)/223 | (equation 1)
{0 x+y = 2970987/223 | (equation 2)

Divide equation 1 by -5165:
{x+0 y = 2856/1115 | (equation 1)
{0 x+y = 2970987/223 | (equation 2)

Collect results:

  {x = 2856/1115 , y = 2970987/223



Solve the following system using substitution:
{y = 4050 x + 2949
{y = 5165 x + 93

Substitute y = 4050 x + 2949 into the second equation:
{y = 4050 x + 2949
{4050 x + 2949 = 5165 x + 93

In the second equation, look to solve for x:
{y = 4050 x + 2949
{4050 x + 2949 = 5165 x + 93

Subtract 5165 x + 2949 from both sides:
{y = 4050 x + 2949
{-1115 x = -2856

Divide both sides by -1115:
{y = 4050 x + 2949
{x = 2856/1115

Substitute x = 2856/1115 into the first equation:
{y = 2970987/223
{x = 2856/1115

Collect results in alphabetical order:
  {x = 2856/1115, y = 2970987/223

On monday,mrs.wise bought 3 lbs of apples at $4per lb= 4*3=$12on tuesday ,20%off and she buy 5 lbs of apples = $4-20%=3.20*5lb=$16example: other wise when she buy 5lbs on monday she have to spend 4*5=20