What is the equation of a line that passes through points (-3,0.5) and (3, -0.5)? a.) y = -1/6x b.) y = -6x c.) y = -1/6x + 1 d.) y = -6x - 17.5

The slope-intercept form:

m - slope

b - y-intercept

The formula of  slope:

We have the points (-3, 0.5) and (3, -0.5). Substitute:

Put it to the equation of a line:

Put the coordinates of the point (3, -0.5) to the equation of a line:

         add 0.5 to both sides

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

b

step-by-step explanation: