basketball coach asks half his players to stretch before each game; the other players do not stretch. after a month of games, she analyzes their playing stats. she concludes the stretching improve their performance on the court. how can the coach test the means to be sure the results not likely to happen by chance? (3 points)she can pick players at random and analyze their playing stats without calculating means. she can analyze the two groups by calculating the means and the difference of the means. she can rerandomize the results by separating the two groups randomly, then calculate the means and the difference of the means. she can pick the players she wants to analyze based on the best stats.

C.  She can rerandomize the results by separating the two groups randomly, then calculate the means and the difference of the means.

She can re randomize the results by separating the two groups randomly, then calculate the means and the difference of the means

Step-by-step explanation:

For calculating the mean, we sum the values and divide the sum by the number of cases.

Here the coach already divided the players in 2 groups- one who stretches and one who don't and wants to conclude at the end. So, the best possible answer is - She can re randomize the results by separating the two groups randomly, then calculate the means and the difference of the means.

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.