Brainliest to person who does all steps, keep it simple and easy to understand the length of a rectangular floor is 4 ft. longer than its width w. the area of the floor is 525 ft^2. a) draw a picture of the situation. b) write a quadratic equation for the area in terms of w that represents the situation. c) what are the dimensions of the floor? explain how you found them.

Assume that the width of the floor is w.
The length is 4 ft longer than the width.
This means that:
Length = 4 + w

Part (a):
The drawing of the situation is shown in the attached image

Part (b):
Area of the rectangle is calculated as follows:
area = length * width
area = (w + 4) * w
area = w² + 4w
We are given that the area is 525 ft²
This means that:
525 = w² + 4w

Part (c):
To get the dimensions of the floor, we will need to solve the quadratic equation from part b.
area = w² + 4w
525 = w² + 4w
w² + 4w - 525 = 0
(w-21)(w+25) = 0
either w-21 = 0 ............> w = 21 ft .........> accepted solution
or w+25 = 0 ............> w = -25 ...........> rejected solution as the length cannot be negative
Now, we know that:
length = w + 4
length = 21 + 4
length = 25 ft
This means that:
length of floor = 25 ft
width of floor = 21 ft

Hope this helps :)

A=bxh3.2x1.8=5.76 centimeters square