1. the formula represents the kinetic energy k of an object with mass m and velocity v. k=1/2mv^2 solve for v. a. v=±2k√m b. v=±2km√m c. v=±2km−−−−√ d. v=±12km2 2. the formula gives the volume v of a right cylinder with radius r and height h. v=πr2h solve for r. a. r=vπh√h b. r=vπh√πh c. r=πvh−−−√ d. r=vπh−−−−√ 3. solve for t. d=−16t2+4t a. t=18±1−4d√8 b. t=12±41−4d−−−−−√ c. t=12±41−4d√2 d. t=8±1−4d−−−−−√

number 1

You will find that it is easier to do your algebra BEFORE plugging in the numbers. You have KE = 1 2 m v 2 KE=12mv2 then 2 KE = m v 2 2KE=mv2 then 2 KE m = v 2 2KEm=v2 so v = √ 2 KE m v=2KEm Now you can substitute in your numbers and arrive at the numeric solution.

number 2

v = πr²h

Solve for r

We can take the root of both sides, then solve from there

Thus,

The correct answer is option A

number 3

Since

t

is on the right side of the equation, switch the sides so it is on the left side of the equation.

16

t

2

=

d

Divide each term by

16

and simplify.

t

2

=

d

16

Take the square root of both sides of the equation to eliminate the exponent on the left side.

t

=

±

√

d

16

The complete solution is the result of both the positive and negative portions of the solution.

t = √ d 4 , − √ d 4

d

step-by-step explanation: