Mathematics, 28.07.2019 01:30, teamroper35
Look at the right triangle abc: right triangle abc has a right angle at b. segment bd meets segment ac at a right angle. a student made the following chart to prove that ab2 + bc2 = ac2: first one is the statement and the second one is the justification 1. triangle abc is similar to triangle bdc 1. angle abc = angle bdc and angle bca = angle bcd 2. bc2 = ac • dc 2. bc ÷ dc = bc ÷ ac because triangle abc is similar to triangle bdc 3. triangle abc is similar to triangle abd 3. angle abc = angle adb and angle bac = angle bad 4. ab2 = ac • ad 4. ab ÷ ad = ac ÷ ab because triangle abc is similar to triangle adb 5. ab2 + bc2 = ac • ad + ac • dc = ac (ad + dc) 5. adding statement 1 and statement 2 6. ab2 + bc2 = ac2\ 6. ad + dc = ac what is the first incorrect justification?
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