∆abc is reflected about the line y = -x to give ∆a'b'c' with vertices a'(-1, 1), b'(-2, -1), c(-1, 0). what are the vertices of ∆abc? a. a(1, -1), b(-1, -2), c(0, -1) b. a(-1, 1), b(1, 2), c(0, 1) c. a(-1, -1), b(-2, -1), c(-1, 0) d. a(1, 1), b(2, -1), c(1, 0) e. a(1, 2), b(-1, 1), c(0, 1)

b. A(-1, 1), B(1, 2), C(0, 1)

Step-by-step explanation:

Reflecting across the line y = -x switches the x- and y-coordinates and negates them.  Algebraically, it maps every point (x, y) → (-y, -x).

This means that for A'(-1, 1), -y = -1 and -x = 1; this means y = 1 and x = -1, so A is (-1, 1).

For B'(-2, -1), -y = -2 and -x = -1; this means y = 2 and x = 1, so B is (1, 2).

For C'(-1, 0), -y = -1 and -x = 0; this means y = 1 and x = 0, so C is (0, 1).

i'm pretty sure it's 477,585,296, but perhaps my math is incorrect.

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says