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 " x = 110 " .


180 – 140 = 40° .  That is the angle of one side of the triangle given.

Note:  The particular angle in the  "unknown" angle in the triangle given, near the "140° angle",  is supplementary to the "140° angle" ; and supplementary angles add up to "180° " .

180 – 110 = 70° .  That is the angle of one side of the triangle given. 

Note:  This particular angle in the  "unknown" angle in the triangle given, near the "110° angle",  is supplementary to the "140° angle" ; and supplementary angles add up to "180° " .

We now know that 2 (TWO) of the measurements given in the triangle shown are:  "40° " and "70° " .    

Now, we shall find the measurement of the remaining angle in the triangle shown.

Note that in any triangle, all three (3) angles add up to "180° " .

So, to find the remaining angle in the triangle given {that is; the "angle nearest to "x"} ;  we do so as follows:

   180 – (40 + 70) = 180 – 110 = 70° .


    →  Now, since "x" is supplementary to this "70° " angle;  
& since "supplementary angles" add up to " 180° " ; 

    →  x = 180 – 70 = 110° .

   
    →  x = 110 . 


OTHER METHOD:


The given "110° angle (in the "image attached") and "x" are
"alternate exterior angles" ; and "alternate exterior angles are equal; 

  as such:  " x = 110 " .