Factor to find the zeros of the function defined by the quadratic expression. 9x2 − 63x − 702

Not that it will help all that much, but you could take out 9 as a common factor.
9(x^2 - 7x - 78) = 0 so since 9 but itself can't produce a zero, we can divide by 9
x^2 - 7x - 78 = 0 
There are 3 factors of 78
2 13 and 3
6 and 13 differ by 7 (6 comes from putting the 2 and 3 together by multiplying.
(x - 13)(x + 6) = 0 

x -13 =0
x = 13

x + 6 = 0
x = - 6

The two zeros are (-6,0) and (13,0)

I’m not sure about that