Which function increases by 1/3 every time the x-increases by 1? a) y = 3x b) y = 3x + 1 c) y = (1/3)x d) y = 1/3x + 1

C)y = (1/3)x  

D)y = 1/3x + 1

Step-by-step explanation:

One simple method to evaluate this question is by inserting the values of x in the options:

A) If x =1

y = 3*(1) = 3

for x =2

y = 3*(2) = 6

=> Value of function is increasing by the factor 3, so option is wrong.

B) If x =1

y = 3*(1) +1 = 4

for x =2

y = 3*(2) + 1 = 7

=> Value of function is increasing by the factor 3, so option is wrong.

C) If x =1

y = (1/3)*(1) = 1/3

for x =2

y = (1/3)*(2) = 2/3

for x =3

y = (1/3)*(3) = 3/3 = 1

=> Value of function is increasing by the factor 1/3, so option is correct.

D) If x =1

y = (1/3)*(1) + 1 = 4/3

for x =2

y = (1/3)*(2) + 1 = 5/3

for x =3

y = (1/3)*(3) +1 = 3/3 + 1  = 2

=> Value of function is increasing by the factor 1/3, so option is also correct.

d i think

step-by-step explanation:

answer: y = 3/2 x - 3

y = 1/8 x - 3/4 that would be your correct option

step-by-step explanation: w