Productivity for an agency was 350,000 units more for the second year than the first, and productivity for the third year was double the productivity for the second year. if productivity for the third year was 806,000 units, what was productivity for the first year?

if we call P1 to the productivity of the first year, P2 for the second, and so on, then:

1 ) P2 - P1 = 350,000

2) P3 = 2*P2

and P3 = 806,000

now we can put this value on the equation 2, and obtain the value of P2

then P2 = P3/2 = 806,000/2 = 403,000

now we can put this value on equation 1, and obtain the value of P1.

P2 - P1 = 403,000 - P1 = 350,000

P1 = 403,000 - 350,000 = 53,000

So the productivity in the first year is 53,000 units.

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!