Mathematics, 28.07.2019 15:30, EricaLSH7624
Write the complex number in the form a + bi. square root of six (cos 315° + i sin 315°) (2 points)
Answers: 1
![\bf z=\stackrel{r}{6}[cos(\stackrel{\theta }{315^o})+i~sin(\stackrel{\theta }{315^o})]\qquad \begin{cases} a=x=rcos(\theta )\\ b=y=rsin(\theta )\\ ----------\\ a=6cos(315^o)\\ \qquad 6\left( \frac{\sqrt{2}}{2} \right)\\ \qquad 3\sqrt{2}\\ b=6sin(315^o)\\ \qquad 6\left( -\frac{\sqrt{2}}{2} \right)\\ \qquad -3\sqrt{2} \end{cases} \\\\\\ z=(~3\sqrt{2}~,~-3\sqrt{2}~)\implies z=3\sqrt{2}-3\sqrt{2}~i](/tpl/images/0143/3401/d1a35.png)
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Write the complex number in the form a + bi. square root of six (cos 315° + i sin 315°) (2 points)...
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