Mathematics, 28.07.2019 21:00, rndschopplein
The equation for the circle is: x^2+y^2−12x+6y−19=0 . what is the center of the circle? question 12 options: (-6, 3) (12, -6) (6, -3) (-12, 6)
Answers: 1
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The equation for the circle is: x^2+y^2−12x+6y−19=0 . what is the center of the circle? question 1...
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