Write an equation for the line in the given form. slope is −5 and (6, 4) is on the line; standard form

  5x +y = 34

Step-by-step explanation:

Since a point and slope are given, it is convenient to start with point-slope form, then rearrange the equation to put it into standard form.

For slope m through point (h, k), the point-slope form of the equation of a line is usually written ...

  y -k = m(x -h)

For m=-5 and (h, k) = (6, 4), the equation is ...

  y -4 = -5(x -6)

  y -4 = -5x +30 . . . . . eliminate parentheses

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Standard form looks like ...

  ax + by = c

where a > 0 and GCD(a, b, c) = 1. Here's how we can get there.

  5x +y -4 = 30 . . . . . . add 5x

  5x +y = 34 . . . . . . . . . add 4 to get standard form.

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

is this part of a question or something