Find the dimensions of a rectangle with perimeter 108 m whose area is as large as possible. (if both values are the same number, enter it into both blanks.)

The dimensions of the rectangle with perimeter 108 and whose area is large as possible if the both values are the same number. For the rectangle to have maximum area, the dimensions should be equal.
Let the dimensions be x
thus the perimeter will be:
2(x+x)=108
2(2x)=108
4x=108
x=27
thus for the rectangle to have a maximum area the dimensions should be 27m by 27 m