Given sinx=0.9 , what is cosx ? enter your answer as a decimal in the box. round only your final answer to the nearest hundredth.

It is given sinx=0.9 .We need to find cosx.

We use the identity :

Substituting sinx=0.9

Substracting 0.81 both sides:

Taking root of both sides cosx=0.435

Rounding to nearest hundredth

cosx=0.44.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

hi! i think the answer is 1/2 : )